Question

answer the question below using the following balanced equation:
3 si(s) + 2 n₂(g) → 1 si₃n₄(s)
given that si is the limiting reactant, use this information to calculate how many moles of si₃n₄ would be produced in this reaction.
now lets say we have:
16.24 moles of si
15.38 moles of n₂
how many moles of si₃n₄ would be produced in this reaction?
moles si3n4

Explanation:

Step1: Analyze the mole ratio

From the balanced equation \(3Si(s)+2N_2(g)\to1Si_3N_4(s)\), the mole ratio of \(Si\) to \(Si_3N_4\) is \(3:1\).

Step2: Calculate moles of \(Si_3N_4\)

We have \(n(Si) = 16.24\) moles. Using the mole ratio \(\frac{n(Si_3N_4)}{n(Si)}=\frac{1}{3}\), so \(n(Si_3N_4)=\frac{1}{3}\times n(Si)\).
Substitute \(n(Si) = 16.24\) moles: \(n(Si_3N_4)=\frac{16.24}{3}\)

Answer:

\(5.41\) moles