Question

analyze the chemical formula to correcting identify the number of atoms that compromise the given compound. li₂co₃ lithium = 1 carbon = 3 oxygen = 3 lithium = 2 carbon = 1 oxygen = 3 lithium = 2 cobalt = 3 lithium = 2 cobalt = 3

Explanation:

Step1: Analyze Lithium ($Li$)

In $Li_2CO_3$, the subscript of $Li$ is $2$, so the number of lithium atoms is $2$.

Step2: Analyze Carbon ($C$)

In $Li_2CO_3$, the subscript of $C$ is $1$ (when no subscript is written, it is assumed to be $1$), so the number of carbon atoms is $1$.

Step3: Analyze Oxygen ($O$)

In $Li_2CO_3$, the subscript of $O$ is $3$, so the number of oxygen atoms is $3$.

Answer:

Second option: Lithium = 2, Carbon = 1, Oxygen = 3