Question

aluminum and oxygen
express your answer as a chemical formula.
a chemical reaction does not occur for this question.
submit request answer
part b
beryllium and iodine
express your answer as a chemical formula.
a chemical reaction does not occur for this question.
submit request answer
part c
calcium and sulfur
express your answer as a chemical formula.

Explanation:

Part A: aluminum and oxygen

Step1: Determine the charges

Aluminum (\(Al\)) has a charge of \(+3\) (\(Al^{3+}\)), oxygen (\(O\)) has a charge of \(- 2\) (\(O^{2 -}\)).

Step2: Use the criss - cross method

To balance the charges, we take the absolute value of the charges and swap them as sub - scripts. So for \(Al\) and \(O\), the formula is \(Al_{2}O_{3}\).

Part B: beryllium and iodine

Step1: Determine the charges

Beryllium (\(Be\)) has a charge of \(+2\) (\(Be^{2+}\)), iodine (\(I\)) has a charge of \(-1\) (\(I^{-}\)).

Step2: Use the criss - cross method

Using the criss - cross method, the formula for the compound formed by \(Be\) and \(I\) is \(BeI_{2}\).

Part C: calcium and sulfur

Step1: Determine the charges

Calcium (\(Ca\)) has a charge of \(+2\) (\(Ca^{2+}\)), sulfur (\(S\)) has a charge of \(-2\) (\(S^{2 -}\)).

Step2: Simplify the formula

When we use the criss - cross method (\(Ca_{2}S_{2}\)), we can simplify it. Dividing both sub - scripts by 2 gives \(CaS\).

Answer:

Part A: \(Al_{2}O_{3}\)
Part B: \(BeI_{2}\)
Part C: \(CaS\)