Question

aluminum has a frequency threshold of 9.846 × 10¹⁴ hz. which best explains what will happen when light with a frequency below the frequency threshold strikes aluminum?
electrons will be ejected immediately.
no electrons will be ejected.
electrons will start being ejected several seconds after the light strikes the aluminum.
no electrons will be ejected unless the intensity is very high.

Explanation:

According to the photoelectric effect, for electrons to be ejected from a metal (in this case aluminum), the frequency of the incident light must be at least equal to the frequency threshold of the metal. If the frequency of the incident light is below the frequency threshold, no electrons will be ejected, regardless of the light's intensity. This is because the energy of a photon is given by \(E = h
u\) (where \(h\) is Planck's constant and \(
u\) is the frequency). If the photon energy (\(h
u\)) is less than the work - function (related to the frequency threshold, \(W_0=h
u_0\)), electrons cannot overcome the binding energy in the metal.

Answer:

No electrons will be ejected.