Question

for a 3.0 s, alex exerts a net force of 10.0 n on a 6.7 kg shopping cart that was initially at rest. use the above information to answer questions 24 - 26. 32. the acceleration of the cart is (a) 9.8 m/s² (b) 1.49 m/s² (c) 5.6 m/s² (d) none of the above

Explanation:

Step1: Recall Newton's second - law

Newton's second - law is $F = ma$, where $F$ is the net force, $m$ is the mass, and $a$ is the acceleration. We can solve for $a$: $a=\frac{F}{m}$.

Step2: Substitute the given values

Given $F = 10.0\ N$ and $m = 6.7\ kg$. Then $a=\frac{10.0\ N}{6.7\ kg}\approx1.49\ m/s^{2}$.

Answer:

B. $1.49\ m/s^{2}$