Question

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question 2 of 37
balance the following chemical equation (if necessary).
nh₃(g) + o₂(g) → no(g) + h₂o(g)

Explanation:

Step1: Balance hydrogen atoms

Let's assume the coefficient of \(NH_3\) is \(a\), \(O_2\) is \(b\), \(NO\) is \(c\), and \(H_2O\) is \(d\).
For hydrogen atoms: \(3a = 2d\). Let \(a = 2\), then \(d=3\).

Step2: Balance nitrogen atoms

For nitrogen atoms: \(a=c\). Since \(a = 2\), then \(c = 2\).

Step3: Balance oxygen atoms

For oxygen atoms: \(2b=c + d\). Substitute \(c = 2\) and \(d = 3\) into it, we get \(2b=2 + 3=5\), so \(b=\frac{5}{2}\).
Multiply each coefficient by 2 to get rid of the fraction. So \(a = 4\), \(b = 5\), \(c = 4\), \(d = 6\).

Answer:

\(4NH_3(g)+5O_2(g)\to4NO(g)+6H_2O(g)\)