Question

an airplane flies 56 miles due north and then 33 miles due east. how many miles is the plane from its starting point?
we dont have enough information.
45.4 miles
65 miles
89 miles

Explanation:

Step1: Apply Pythagorean theorem

The plane's path forms a right - triangle. Let \(a = 56\) (north - ward distance) and \(b=33\) (east - ward distance). The distance \(d\) from the starting point is given by \(d=\sqrt{a^{2}+b^{2}}\).

Step2: Calculate \(a^{2}\) and \(b^{2}\)

\(a^{2}=56^{2}=3136\), \(b^{2}=33^{2}=1089\).

Step3: Sum \(a^{2}\) and \(b^{2}\)

\(a^{2}+b^{2}=3136 + 1089=4225\).

Step4: Take the square root

\(d=\sqrt{4225}=65\).

Answer:

65 miles