Question

after school, seki and fernando walk home. seki walks 5 blocks east and 10 blocks north. fernando walks 10 blocks east and 8 blocks south. on the graph, the school is located at the origin. determine the distance between sekis house (point s) and fernandos house (point f). enter the coordinates of the two given points and then calculate the distance between them. coordinates (x1, y1) of point s: (?,?) coordinates (x2, y2) of point f: (?,?) d = \sqrt{(x2 - x1)^2+(y2 - y1)^2}

Explanation:

Step1: Find Seki's coordinates

East - positive x - direction, north - positive y - direction. Seki walks 5 blocks east and 10 blocks north, so coordinates of point S are $(5,10)$.

Step2: Find Fernando's coordinates

Fernando walks 10 blocks east and 8 blocks south (negative y - direction). So coordinates of point F are $(10, - 8)$.

Step3: Apply distance formula

The distance formula is $d=\sqrt{(x_2 - x_1)^2+(y_2 - y_1)^2}$. Here $x_1 = 5,y_1 = 10,x_2=10,y_2=-8$.
$d=\sqrt{(10 - 5)^2+(-8 - 10)^2}=\sqrt{5^2+(-18)^2}=\sqrt{25 + 324}=\sqrt{349}\approx18.68$.

Answer:

Coordinates $(x_1,y_1)$ of point S: $(5,10)$
Coordinates $(x_2,y_2)$ of point F: $(10,-8)$
Distance $d\approx18.68$