Question

according to the bronsted-lowry definition, what acts as the acid when the reaction below proceeds in the forward direction?

$$ mathrm { h } _ { 2 } mathrm { o } + mathrm { hso } _ { 4 } ^ { - } ightleftharpoons mathrm { so } _ { 4 } ^ { 2 - } + mathrm { h } _ { 3 } mathrm { o } ^ { + } $$

select the correct answer below:

$$ mathrm { h } _ { 3 } mathrm { o } ^ { + } $$

$$ mathrm { h } _ { 2 } mathrm { o } $$

$$ mathrm { hso } _ { 4 } ^ { - } $$

$$ mathrm { so } _ { 4 } ^ { 2 - } $$

Explanation:

According to the Bronsted - Lowry definition, an acid is a proton (\(H^{+}\)) donor. In the reaction \(H_{2}O + HSO_{4}^{-}
ightleftharpoons SO_{4}^{2 - }+H_{3}O^{+}\), when the reaction proceeds in the forward direction, \(HSO_{4}^{-}\) donates a proton (\(H^{+}\)) to \(H_{2}O\). \(HSO_{4}^{-}\) loses a proton to form \(SO_{4}^{2 - }\), while \(H_{2}O\) gains a proton to form \(H_{3}O^{+}\).

Answer:

\(HSO_{4}^{-}\)