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Question
e^{8x} - 20 = 127
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e^{8x} - 20 = 127
e^{8x} = \square
8x = \ln(\square)
x \approx \square
Step1: Isolate the exponential term
To solve for \( e^{8x} \), we add 20 to both sides of the equation \( e^{8x}-20 = 127 \).
Step2: Take the natural logarithm
Since \( y = e^{x} \) and \( y=\ln(x) \) are inverse functions, we take the natural logarithm of both sides to solve for \( 8x \).
Using the property \( \ln(e^{a})=a \), we get:
Step3: Solve for \( x \)
We divide both sides by 8 to solve for \( x \).
Calculating the numerical value: \( \ln(147)\approx 4.9904 \), so \( x\approx\frac{4.9904}{8}\approx 0.6238 \) (or more accurately, using a calculator for \( \frac{\ln(147)}{8} \))
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For \( e^{8x}=\boxed{147} \)
For \( 8x = \ln(\boxed{147}) \)
For \( x\approx\boxed{0.62} \) (or more precise \( \frac{\ln(147)}{8}\approx0.6238 \))