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if a 82 kg person is in an elevator moving at a speed of 5 m/s, then wh…

Question

if a 82 kg person is in an elevator moving at a speed of 5 m/s, then what is the persons kinetic energy?
a 410 j
b 1,025 j
c 5 j
d 82 j

Explanation:

Step1: Recall Kinetic Energy Formula

The formula for kinetic energy (KE) is $KE = \frac{1}{2}mv^2$, where $m$ is mass (in kg) and $v$ is velocity (in m/s).

Step2: Substitute Values

Given $m = 82\ \text{kg}$ and $v = 5\ \text{m/s}$. Substitute into the formula:
$KE = \frac{1}{2} \times 82 \times (5)^2$
First, calculate $(5)^2 = 25$. Then, $\frac{1}{2} \times 82 = 41$. Now, multiply $41 \times 25 = 1025$.

Answer:

b. 1,025 J