Question

7x = 4x + 33, options: x = 3, x = 21, x = 88, x = 11

Explanation:

Step1: Subtract 4x from both sides

To solve the equation \(7x = 4x + 33\), we first subtract \(4x\) from both sides to get the \(x\)-terms on one side. This gives us \(7x - 4x = 4x + 33 - 4x\), which simplifies to \(3x = 33\).

Step2: Divide by 3

Next, we divide both sides of the equation \(3x = 33\) by 3 to solve for \(x\). So, \(\frac{3x}{3}=\frac{33}{3}\), which simplifies to \(x = 11\). Wait, no, wait, let's recalculate. Wait, \(7x - 4x = 3x\), and \(4x - 4x = 0\), so we have \(3x = 33\)? Wait, no, 7x - 4x is 3x, and the right side is 33. Then \(x=\frac{33}{3}=11\)? Wait, but let's check again. Wait, the original equation is \(7x = 4x + 33\). Subtract 4x: \(7x - 4x = 33\) → \(3x = 33\) → \(x = 11\)? Wait, but wait, maybe I made a mistake. Wait, 7x - 4x is 3x, so 3x = 33, so x = 11. But let's check the options. The options are x=3, x=21, x=88, x=11. So the correct answer is x=11. Wait, but let's verify by plugging back in. If x=11, left side: 711=77. Right side: 411 +33=44+33=77. So yes, x=11 is correct. Wait, but earlier when I did 3x=33, x=11. So the correct solution is x=11.

Answer:

x = 11 (the option with x=11)