Question

4.60×10²³ lead atoms
m = g
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Explanation:

Step1: Recall Avogadro's number and molar mass of lead

Avogadro's number is \(6.022\times10^{23}\) atoms/mol, and the molar mass of lead (Pb) is \(207.2\) g/mol.

Step2: Calculate moles of lead atoms

Moles (\(n\)) = number of atoms / Avogadro's number. So \(n=\frac{4.60\times10^{23}\text{ atoms}}{6.022\times10^{23}\text{ atoms/mol}}\approx0.764\) mol.

Step3: Calculate mass of lead

Mass (\(m\)) = moles × molar mass. So \(m = 0.764\) mol × \(207.2\) g/mol \(\approx158\) g.

Answer:

\(158\) (or more precisely, around \(158\) when calculated, the exact value can be \( \frac{4.60\times10^{23}}{6.022\times10^{23}}\times207.2\approx158\) g)