Question

c₃h₈ + 5o₂ → 4h₂o + 3co₂
model:

atoms:

mass:

Explanation:

Step1: Count Carbon Atoms

For reactants: In \(C_3H_8\), the number of \(C\) atoms is \(3\).
For products: In \(3CO_2\), the number of \(C\) atoms is \(3\times1 = 3\).

Step2: Count Oxygen Atoms

For reactants: In \(5O_2\), the number of \(O\) atoms is \(5\times2=10\).
For products: In \(4H_2O\), there are \(4\times1 = 4\) \(O\) atoms; in \(3CO_2\), there are \(3\times2 = 6\) \(O\) atoms. Total \(O\) atoms in products: \(4 + 6=10\).

Step3: Count Hydrogen Atoms

For reactants: In \(C_3H_8\), the number of \(H\) atoms is \(8\).
For products: In \(4H_2O\), the number of \(H\) atoms is \(4\times2 = 8\).

Answer:

Element	# in Reactants	# in Products
\(O\)	\(10\)	\(10\)
\(H\)	\(8\)	\(8\)