Question

58 in area = 4872 in²

Explanation:

Step1: Recall the formula for the area of a rectangle

The area formula for a rectangle is \( A = l\times w\), where \(A\) is the area, \(l\) is the length, and \(w\) is the width. In this case, \(A = 4872\space in^{2}\) and \(w = 58\space in\), and we need to find \(l\).

Step2: Solve for the length \(l\)

Using the formula \(l=\frac{A}{w}\), substitute \(A = 4872\) and \(w = 58\). So \(l=\frac{4872}{58}\).

$$
LATEXBLOCK0
$$

Answer:

The length of the rectangle is \(84\space in\)