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2 (4x - y = 1) 8(-5x + 2y = 4) 8x - 2y = 2 -40x + 16y = 32 \\overline{3…

Question

2 (4x - y = 1)
8(-5x + 2y = 4)

8x - 2y = 2
-40x + 16y = 32
\overline{3x + 0y = 6}

solve for x:
3x = 6

x = \boxed{}
(try button next to the box)

Explanation:

Step1: Isolate x via division

Divide both sides of $3x=6$ by 3.
$\frac{3x}{3}=\frac{6}{3}$

Step2: Simplify to find x

Calculate the quotient on both sides.
$x=2$

Answer:

$x=2$