Question

4.46 q: the diagram represents a block at rest on an incline. which diagram best represents the forces acting on the block? (f, = frictional force, f, = normal force, and f = weight.)

Explanation:

Step1: Analyze the direction of weight force

The weight force \(F_w\) always acts vertically downward.

Step2: Analyze the direction of normal force

The normal force \(F_N\) is perpendicular to the surface of the incline.

Step3: Analyze the direction of frictional force

Since the block is at rest on the incline, the frictional force \(F_f\) acts up - the - incline to oppose the tendency of the block to slide down.

Looking at the options:

• In option (1), the direction of \(F_N\) is not perpendicular to the incline surface.
• In option (2), \(F_w\) is not acting vertically downward.
• In option (3), \(F_w\) is not acting vertically downward.
• In option (4), \(F_w\) acts vertically downward, \(F_N\) is perpendicular to the incline surface, and \(F_f\) acts up - the - incline.

Answer:

(4)