Question

a 0.45 kg football traveling at a speed of 22 meters per second is caught by an stationary receiver. if the football comes to rest in the receivers arms, the change in momentum of the football is

a -1,848 kg.m/s
b 1,848 kg.m/s
c -9.9 kg.m/s
d 9.9 kg.m/s

Explanation:

Step1: Recall the formula for change in momentum

The formula for change in momentum \(\Delta p = p_{final}-p_{initial}\), and momentum \(p = mv\).

Step2: Find the initial and final momentum

Given \(m = 0.45\space kg\), \(v_{initial}=22\space m/s\), \(v_{final} = 0\space m/s\).
Initial momentum \(p_{initial}=mv_{initial}=0.45\times22 = 9.9\space kg\cdot m/s\).
Final momentum \(p_{final}=mv_{final}=0.45\times0=0\space kg\cdot m/s\).

Step3: Calculate the change in momentum

\(\Delta p=p_{final}-p_{initial}=0 - 9.9=- 9.9\space kg\cdot m/s\)

Answer:

C. -9.9 kg.m/s