Question

a 43.40 mg sample of an alcohol contains 15.10 mg of o, 22.60 mg of c, and 5.70 mg of h. what is its percent composition of carbon? % c

Explanation:

Step1: Recall the formula for percent composition

Percent composition of an element \(=\frac{\text{Mass of the element}}{\text{Mass of the sample}}\times100\%\)

Step2: Substitute the values

Here, mass of carbon \(m_{C} = 22.60\space mg\) and mass of the sample \(m_{sample}=43.40\space mg\)
Percent composition of carbon \(=\frac{22.60}{43.40}\times 100\%\)

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Answer:

\(52.1\%\)