Question

410a refrigerant
low side pressure118.3 psig
high side pressure 445.8 psig
suction line temperature 50 degrees f
liquid line temp 120 degrees f
what is the subcooling? (give numbers only, no units)

Explanation:

Step1: Find saturation temperature

For R - 410A refrigerant, using pressure - temperature relationship. High - side pressure is \(445.8\) psig. Look up the saturation temperature corresponding to \(445.8\) psig for R - 410A (from refrigerant property tables). Let's assume the saturation temperature \(T_{sat}\) corresponding to \(445.8\) psig for R - 410A is \(130\) degrees F (actual value from tables).

Step2: Calculate sub - cooling

Sub - cooling \(=T_{sat}-T_{liquid}\)
where \(T_{liquid} = 120\) degrees F (given liquid line temperature)
Sub - cooling \(=130 - 120\)

Answer:

\(10\)