Question

\\\frac{x^2 + 3x - 28}{3x - 12}\\

\\\frac{x + ?}{ }\\

Explanation:

Factor the numerator and denominator

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Simplify the expression by canceling common factors

$$ \frac{x^2 + 3x - 28}{3x - 12} = \frac{(x + 7)(x - 4)}{3(x - 4)} = \frac{x + 7}{3} \quad (x eq 4) $$

Identify the missing values

$$ \frac{x + [?]}{[\quad]} = \frac{x + 7}{3} $$

Answer:

Simplify the expression:

$$\frac{x^2 + 3x - 28}{3x - 12}$$

The simplified expression is <blank>\(\frac{x + 7}{3}\)</blank>.