Question

\\(3m^4n^7)^4 \div (9m^3n^2)^2\\

Explanation:

Apply power of a product rule to both terms

$$
LATEXBLOCK0
$$

Divide the simplified terms

$$ \frac{81m^{16}n^{28}}{81m^6n^4} = \frac{81}{81} \cdot m^{16-6} \cdot n^{28-4} = m^{10}n^{24} $$

Answer:

\((3m^4n^7)^4 \div (9m^3n^2)^2 =\) <blank>\(m^{10}n^{24}\)</blank>