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3h₂so₄ + 2b(oh)₃ → b₂(so₄)₃ + 6h₂o what is the denominator of the mole …

Question

3h₂so₄ + 2b(oh)₃ → b₂(so₄)₃ + 6h₂o
what is the denominator of the
mole ratio between boron sulfate
and sulfuric acid?
1 mol b₂(so₄)₃
? mol h₂so₄
fill in the green blank.

Explanation:

Step1: Analyze the balanced chemical equation

The balanced chemical equation is \(3H_2SO_4 + 2B(OH)_3 \to B_2(SO_4)_3+6H_2O\).

Step2: Determine the mole ratio

From the equation, the mole ratio of \(B_2(SO_4)_3\) to \(H_2SO_4\) is \(1:3\).

Answer:

\(3\)