Question

1. find the perimeter of rectangle abcd. find the area of rectangle abcd.

Explanation:

Step1: Calculate length of side AB

Since A(-2,-2) and B(-2,4), the length of AB is the difference in y - coordinates. Using the formula \(d = |y_2 - y_1|\), we have \(AB=|4 - (-2)|=6\).

Step2: Calculate length of side BC

Since B(-2,4) and C(6,4), the length of BC is the difference in x - coordinates. Using the formula \(d = |x_2 - x_1|\), we have \(BC=|6-(-2)| = 8\).

Step3: Calculate the perimeter of rectangle ABCD

The perimeter \(P\) of a rectangle is given by \(P = 2(l + w)\), where \(l\) and \(w\) are the length and width. Here \(l = 8\) and \(w = 6\), so \(P=2(8 + 6)=28\).

Step4: Calculate the area of rectangle ABCD

The area \(A\) of a rectangle is given by \(A=l\times w\). Here \(l = 8\) and \(w = 6\), so \(A=8\times6 = 48\).

Answer:

Perimeter: 28
Area: 48