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33. use the egg car collision data in the table below to answer the fol…

Question

  1. use the egg car collision data in the table below to answer the following questions
carmass (kg)change in speed (m/s)collision time (s)force of impact (n)
b1.5 kg4 m/s0.05 s
c1.5 kg4 m/s0.12 s

force of impact = \\(\frac{mass \times change\\ in\\ speed}{time}\\)

a. calculate the force of impact for car a, car b, and car c. write your answers in the table above.

b. which car had the greater force of impact? explain how you know using the data and your calculations.

c. which car will keep the egg safer? explain how you know using data and your calculations.

  1. what did you learn about how real safety features (like crumple zones, airbags, seat belts) reduce force during a collision? include how this connects to your egg car design.
  1. what were you being asked to do for the egg car project? what problem were you trying to solve?

Explanation:

Part a

Step1: Recall the formula

The formula for force of impact is given by \( \text{Force of Impact} = \frac{\text{mass} \times \text{change in speed}}{\text{time}} \)

Step2: Calculate for Car A

For Car A: mass \( m = 1.5 \, \text{kg} \), change in speed \( \Delta v = 4 \, \text{m/s} \), time \( t = 0.09 \, \text{s} \)

$$ \text{Force}_A=\frac{1.5\times4}{0.09}=\frac{6}{0.09}\approx 66.67 \, \text{N} $$

Step3: Calculate for Car B

For Car B: mass \( m = 1.5 \, \text{kg} \), change in speed \( \Delta v = 4 \, \text{m/s} \), time \( t = 0.05 \, \text{s} \)

$$ \text{Force}_B=\frac{1.5\times4}{0.05}=\frac{6}{0.05} = 120 \, \text{N} $$

Step4: Calculate for Car C

For Car C: mass \( m = 1.5 \, \text{kg} \), change in speed \( \Delta v = 4 \, \text{m/s} \), time \( t = 0.12 \, \text{s} \)

$$ \text{Force}_C=\frac{1.5\times4}{0.12}=\frac{6}{0.12}= 50 \, \text{N} $$
Part b
Brief Explanations

To find which car has the greater force of impact, we compare the forces calculated in part (a). Car B has a force of \( 120 \, \text{N} \), Car A has \( \approx 66.67 \, \text{N} \) and Car C has \( 50 \, \text{N} \). Since \( 120>66.67 > 50 \), Car B has the greatest force of impact.

Part c
Brief Explanations

A lower force of impact is better for keeping the egg safe (as a lower force means less impact on the egg). From part (a), Car C has the lowest force of impact (\( 50 \, \text{N} \)) among the three cars. So, Car C will keep the egg safer.

Part a Answer:
  • Car A: \( \approx 66.67 \, \text{N} \)
  • Car B: \( 120 \, \text{N} \)
  • Car C: \( 50 \, \text{N} \)
Part b Answer:

Car B. Because its force of impact (\( 120 \, \text{N} \)) is greater than that of Car A (\( \approx 66.67 \, \text{N} \)) and Car C (\( 50 \, \text{N} \)).

Part c Answer:

Car C. Because it has the lowest force of impact (\( 50 \, \text{N} \)), so the impact on the egg will be the least, keeping it safer.

Answer:

A lower force of impact is better for keeping the egg safe (as a lower force means less impact on the egg). From part (a), Car C has the lowest force of impact (\( 50 \, \text{N} \)) among the three cars. So, Car C will keep the egg safer.

Part a Answer:
  • Car A: \( \approx 66.67 \, \text{N} \)
  • Car B: \( 120 \, \text{N} \)
  • Car C: \( 50 \, \text{N} \)
Part b Answer:

Car B. Because its force of impact (\( 120 \, \text{N} \)) is greater than that of Car A (\( \approx 66.67 \, \text{N} \)) and Car C (\( 50 \, \text{N} \)).

Part c Answer:

Car C. Because it has the lowest force of impact (\( 50 \, \text{N} \)), so the impact on the egg will be the least, keeping it safer.