Question

1. a professional football quarterback throws a ball 32 yards down field to a receiver at a speed of 60 miles per hour. a mile equals 1,760 yards. once the quarterback releases the ball, the football gets to the receiver in about ___ seconds.

a. 1.1
b. 0.53
c. 0.92
d. 1.9

Explanation:

Step1: Convert speed to yards - per - second

The speed is 60 miles per hour. Since 1 mile = 1760 yards and 1 hour = 3600 seconds, the speed $v$ in yards - per - second is $v=\frac{60\times1760}{3600}=\frac{105600}{3600}=\frac{88}{3}$ yards per second.

Step2: Calculate the time

We know that distance $d = 32$ yards, and the formula for time $t$ is $t=\frac{d}{v}$. Substitute $d = 32$ yards and $v=\frac{88}{3}$ yards per second into the formula: $t=\frac{32}{\frac{88}{3}}=32\times\frac{3}{88}=\frac{96}{88}\approx1.1$ seconds.

Answer:

a. 1.1