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2x² - 9x - 10. 5. perform the operation. (-x² - 3x + 3) - (-x² - 9x + 6)

Question

2x² - 9x - 10.

  1. perform the operation.

(-x² - 3x + 3) - (-x² - 9x + 6)

Explanation:

Step1: Distribute the negative sign

We have the expression \((-x^2 - 3x + 3)-(-x^2 - 9x + 6)\). When we distribute the negative sign to the second polynomial, we get \(-x^2 - 3x + 3 + x^2 + 9x - 6\).

Step2: Combine like terms

  • For the \(x^2\) terms: \(-x^2+x^2 = 0\)
  • For the \(x\) terms: \(-3x + 9x=6x\)
  • For the constant terms: \(3-6=-3\)

Combining these results, we have \(6x - 3\).

Answer:

\(6x - 3\)