Question

2n₂(g) + 5o₂(g) → 2n₂o₅(g)
if 3.22 moles of n₂ react, what
volume of n₂o₅ is produced at stp?
? l n₂o₅

Explanation:

Step1: Determine mole ratio

From the balanced equation \(2N_2(g)+5O_2(g)
ightarrow2N_2O_5(g)\), the mole ratio of \(N_2\) to \(N_2O_5\) is \(2:2\) (or \(1:1\)). So moles of \(N_2O_5\) produced = moles of \(N_2\) reacted = \(3.22\) mol.

Step2: Use STP volume conversion

At STP (Standard Temperature and Pressure: \(0^\circ C\), \(1\) atm), \(1\) mole of any ideal gas occupies \(22.4\) L. So volume of \(N_2O_5\) = moles \(\times\) \(22.4\) L/mol.
Volume = \(3.22\) mol \(\times\) \(22.4\) L/mol = \(72.128\) L.

Answer:

\(72.1\) (or \(72.128\)) L