Question

-2i² (-4i)

Explanation:

Step1: Recall the value of \(i^2\)

We know that in complex numbers, \(i^2 = -1\). So we substitute \(i^2\) with \(-1\) in the expression \(-2i^2(-4i)\).

$$ -2\times(-1)\times(-4i) $$

Step2: Simplify the real - number part

First, calculate \(-2\times(-1)\), which equals \(2\). Then multiply this result by \(-4i\):

$$ 2\times(-4i)= - 8i $$

Answer:

\(-8i\)