Question

2al + 3cl₂ → 2alcl₃
how many grams of aluminum will react fully with 1.25 moles cl₂?
molar mass al: 26.98 g/mol
? g al

Explanation:

Step1: Find mole ratio of Al to Cl₂

From the reaction \(2\text{Al} + 3\text{Cl}_2
ightarrow 2\text{AlCl}_3\), the mole ratio of \(\text{Al}\) to \(\text{Cl}_2\) is \(\frac{2}{3}\).

Step2: Calculate moles of Al

Given moles of \(\text{Cl}_2 = 1.25\space mol\). Using the mole ratio, moles of \(\text{Al}=1.25\space mol\times\frac{2}{3}\).

Step3: Calculate mass of Al

Mass of \(\text{Al}=\text{moles of Al}\times\text{molar mass of Al}\). Molar mass of \(\text{Al}=26.98\space g/mol\). So, mass \(=1.25\times\frac{2}{3}\times26.98\).
First, \(1.25\times\frac{2}{3}=\frac{2.5}{3}\approx0.8333\space mol\). Then, \(0.8333\times26.98\approx22.48\space g\).

Answer:

\(22.5\) (or more precisely \(22.48\))