Question

1. in a chemical equation what is the difference between the terms \synthesis\ and \decomposition\?
2. balance and name the following type of chemical reaction:

c₂h₆ + o₂ → co₂ + h₂o

1. balance and name the following type of chemical reaction

albr₃ + k₃bo₃ → kbr + al₃(bo₃)₃

1. balance and name the following type of chemical reaction:

c₆h₁₂o₆ + o₂ → co₂ + h₂o

1. balance and name the following type of chemical reaction:

nabr + caf₂ → naf + cabr₂

1. balance and name the following type of chemical reaction:

ag₂o → ag + __ o₂

1. which of the following subscripts are incorrect? provide the correct subscripts for those incorrect formulas.

a. css₂ ______
b. ag₄cl ______
c. ca₃o ______
d. al(oh) ______
e. mn₂br ______

1. determine whether the bond is covalent, ionic or both

a. nh₄ ______
b. mgi₂ ______
c. koh ______
d. fe₂s₃ ______
e. h₂o ______
in problems 35 - 37 write the formula for the following compounds:

1. dinitrogen tetroxide ______
2. sodium phosphate ______
3. lead iv acetate ______
4. with respect to the gas laws studied at the beginning of the semester, what does the term inverse represent when dealing with a temperature/pressure equation? ______
5. 2 points: illustrate and balance the following equation: aluminum hydroxide plus hydrogen carbonate produces aluminum

Explanation:

Let's solve question 28: Balancing the chemical equation $\ce{C2H6 + O2 -> CO2 + H2O}$ and naming the reaction type.

Step 1: Balance Carbon atoms

On the left, we have 2 C in $\ce{C2H6}$. So we put a coefficient of 2 in front of $\ce{CO2}$ to balance C:
$\ce{C2H6 + O2 -> 2CO2 + H2O}$

Step 2: Balance Hydrogen atoms

On the left, we have 6 H in $\ce{C2H6}$. So we put a coefficient of 3 in front of $\ce{H2O}$ (since $3\times2 = 6$ H):
$\ce{C2H6 + O2 -> 2CO2 + 3H2O}$

Step 3: Balance Oxygen atoms

On the right, we have $2\times2 + 3\times1 = 4 + 3 = 7$ O. But $\ce{O2}$ is diatomic, so we need to find a coefficient for $\ce{O2}$ such that the number of O is a multiple of 2. Let's multiply all coefficients by 2 to eliminate the fraction:
$2\ce{C2H6} + 7\ce{O2} -> 4\ce{CO2} + 6\ce{H2O}$

Now check:

• C: $2\times2 = 4$ on left; $4\times1 = 4$ on right ✔️
• H: $2\times6 = 12$ on left; $6\times2 = 12$ on right ✔️
• O: $7\times2 = 14$ on left; $4\times2 + 6\times1 = 8 + 6 = 14$ on right ✔️

Step 4: Identify the reaction type

This is a combustion reaction (hydrocarbon + oxygen → carbon dioxide + water).

Answer:

Balanced equation: $\boldsymbol{2\ce{C2H6} + 7\ce{O2} -> 4\ce{CO2} + 6\ce{H2O}}$
Reaction type: Combustion reaction