26) water is always a product in what type of reaction?
27) what are the two products that are always formed in a combustion reaction?
______ + ______
28) when balancing a chemical reaction, what are the large numbers that we adjust?
29) when balancing a chemical reaction, what are the small numbers that we do not change?
30) according to the law of conservation of mass, can atoms be destroyed during a reaction? explain.

in the questions below, put a checkmark next to the equations that violate the law of conservation of mass.
in simple terms, equations that violate the law are not balanced correctly. check each element!
31) ______ 2h₂ + o₂ → 2h₂o 35) ______ na + o₂ → na₂o
32) ______ kcl + br₂ → kbr + cl₂ 36) ______ 2 h₂ + o₂ → 2 h₂o
33) ______ na₂co₃ + 2hcl → 2nacl + h₂o + co₂ 37) ______ 4 h₂ + 2 o₂ → 4 h₂o
34) ______ 2fe₂o₃ + 3c → 4fe + 3co₂ 38) ______ 2h₂ + o₂ → h₂o

use the following reaction to answer the next questions.
h₂o₂(aq) → h₂o(l) + o₂(g)
39) in the reaction above, what does the (l) stand for next to h₂o?
40) in the reaction above, what does the (g) stand for next to h₂o?
41) in the reaction above, what does the (aq) stand for next to h₂o?
42) knowing this information above, what would an (s) symbol stand for?
43) in the reaction above, list the reactant(s):
44) in the reaction above, what does the (aq) stand for next to h₂o?
44) in the reaction above, list the product(s):

Question

26) water is always a product in what type of reaction?
27) what are the two products that are always formed in a combustion reaction?
______ + ______
28) when balancing a chemical reaction, what are the large numbers that we adjust?
29) when balancing a chemical reaction, what are the small numbers that we do not change?
30) according to the law of conservation of mass, can atoms be destroyed during a reaction? explain.

in the questions below, put a checkmark next to the equations that violate the law of conservation of mass.
in simple terms, equations that violate the law are not balanced correctly. check each element!
31) ______ 2h₂ + o₂ → 2h₂o  35) ______ na + o₂ → na₂o
32) ______ kcl + br₂ → kbr + cl₂  36) ______ 2 h₂ + o₂ → 2 h₂o
33) ______ na₂co₃ + 2hcl → 2nacl + h₂o + co₂  37) ______ 4 h₂ + 2 o₂ → 4 h₂o
34) ______ 2fe₂o₃ + 3c → 4fe + 3co₂  38) ______ 2h₂ + o₂ → h₂o

use the following reaction to answer the next questions.
h₂o₂(aq) → h₂o(l) + o₂(g)
39) in the reaction above, what does the (l) stand for next to h₂o?
40) in the reaction above, what does the (g) stand for next to h₂o?
41) in the reaction above, what does the (aq) stand for next to h₂o?
42) knowing this information above, what would an (s) symbol stand for?
43) in the reaction above, list the reactant(s):
44) in the reaction above, what does the (aq) stand for next to h₂o?
44) in the reaction above, list the product(s):

Accepted Answer

### Question 26
# Explanation:
## Step1: Recall reaction types
Neutralization (acid - base) reactions involve an acid and a base reacting. The general form is acid + base → salt + water. For example, $ \ce{HCl + NaOH -> NaCl + H2O} $. Also, some condensation reactions (like in organic chemistry, forming esters) can produce water, but the most common reaction where water is always a product is neutralization (acid - base) or also, in the context of some other reactions, but the key here is that in acid - base neutralization, water is always a product. Another type is the reaction between an acid and a base (neutralization) or also, in the case of combustion of hydrocarbons, water is a product but not always the only one, but for the "always" case, neutralization (acid - base) or sometimes dehydration synthesis (but more commonly, acid - base neutralization). Wait, also, in the reaction of an acid and a base (neutralization), water is always a product. Also, in the formation of hydrates? No, hydrates release water. Wait, the main reaction where water is always a product is acid - base neutralization (reaction between an acid and a base) or also, in the case of some redox reactions? No, more precisely, acid - base neutralization: acid (donates $ \ce{H+} $) and base (donates $ \ce{OH-} $) react to form salt and water ($ \ce{H+ + OH- -> H2O} $). Also, some decomposition reactions? No. So the reaction type where water is always a product is acid - base neutralization (or neutralization reaction) or also, in the context of some other reactions, but the key is that in acid - base neutralization, water is a product. Also, sometimes, in the reaction of a metal hydroxide and an acid, water is formed. So the answer is acid - base neutralization reaction (or neutralization reaction) or also, in some cases, combustion of hydrocarbons produces water, but not always "always" in the sense of the reaction type. Wait, the question is "Water is always a product in what type of reaction?". The correct answer is acid - base neutralization reaction (or neutralization reaction) or also, in the case of some other reactions, but the main one is acid - base neutralization. Alternatively, also, in the reaction of an acid and a base (neutralization) or in the case of some condensation reactions (like forming a peptide bond, producing water), but in general chemistry, the most common is acid - base neutralization.
## Step2: Confirm
In an acid - base neutralization reaction, the $ \ce{H+} $ from the acid and $ \ce{OH-} $ from the base combine to form $ \ce{H2O} $. For example, $ \ce{H2SO4 + 2NaOH -> Na2SO4 + 2H2O} $. So water is always a product here. Also, in some cases, like the reaction of a metal oxide and an acid: $ \ce{CaO + 2HCl -> CaCl2 + H2O} $, water is a product. But the key reaction type where water is always a product is acid - base neutralization (or neutralization) reaction.
# Answer: Acid - base neutralization reaction (or Neutralization reaction, or also, sometimes, combustion of hydrocarbons produces water but not always "always" in the reaction type sense, but the main one is acid - base neutralization. However, more accurately, the reaction type is acid - base neutralization (reaction between an acid and a base) or also, in the context of some other reactions, but the standard answer is acid - base neutralization (or neutralization) reaction. Alternatively, the reaction type is acid - base neutralization (or sometimes, hydrolysis? No, hydrolysis consumes water. So the correct answer is acid - base neutralization reaction (or neutralization reaction).

### Question 27
# Explanation:
## Step1: Recall combustion reaction
A combustion reaction is a reaction between a fuel (usually a hydrocarbon, like $ \ce{CH4} $, $ \ce{C2H5OH} $) and oxygen ($ \ce{O2} $). The general equation for the combustion of a hydrocarbon $ \ce{C_xH_y + O2 -> CO2 + H2O} $. For example, $ \ce{CH4 + 2O2 -> CO2 + 2H2O} $, $ \ce{C2H5OH + 3O2 -> 2CO2 + 3H2O} $. So the two products that are always formed in a combustion reaction (of a hydrocarbon or a compound containing C, H, and maybe O) are carbon dioxide ($ \ce{CO2} $) and water ($ \ce{H2O} $).
## Step2: Confirm
In any complete combustion reaction (where there is sufficient oxygen), the products are carbon dioxide and water. If there is insufficient oxygen, carbon monoxide or carbon can be formed, but the question says "always" formed. So for complete combustion (which is the typical case when we talk about combustion reactions in general chemistry), the two products are carbon dioxide ($ \ce{CO2} $) and water ($ \ce{H2O} $).
# Answer: $ \ce{CO2} $ (Carbon Dioxide) + $ \ce{H2O} $ (Water)

### Question 28
# Explanation:
## Step1: Recall balancing chemical equations
When balancing a chemical reaction, we adjust the coefficients (the large numbers in front of the chemical formulas). For example, in the reaction $ \ce{H2 + O2 -> H2O} $, we put a coefficient of 2 in front of $ \ce{H2} $, 1 (implicit) in front of $ \ce{O2} $, and 2 in front of $ \ce{H2O} $ to balance it: $ \ce{2H2 + O2 -> 2H2O} $. These coefficients are the large numbers we adjust to balance the number of atoms on each side of the equation.
## Step2: Confirm
The coefficients are the stoichiometric coefficients (the large numbers) that we change to balance the equation. The subscripts (small numbers) in the chemical formulas represent the number of atoms of each element in a molecule and are not changed (as changing them would change the identity of the compound).
# Answer: Coefficients (the large numbers in front of chemical formulas)

### Question 29
# Explanation:
## Step1: Recall chemical formula notation
In a chemical formula, the small numbers are the subscripts. For example, in $ \ce{H2O} $, the 2 is a subscript, representing the number of hydrogen atoms in a water molecule. When balancing a chemical reaction, we do not change the subscripts because changing them would change the identity of the compound (e.g., changing $ \ce{H2O} $ to $ \ce{HO} $ would make it a different compound, hydroxyl radical, not water).
## Step2: Confirm
Subscripts in chemical formulas indicate the number of atoms of each element in a molecule (or formula unit for ionic compounds). They are part of the chemical identity of the substance, so we cannot change them when balancing equations. We only change the coefficients (large numbers) to balance the number of atoms.
# Answer: Subscripts (the small numbers in chemical formulas)

### Question 30
# Explanation:
## Step1: Recall Law of Conservation of Mass
The Law of Conservation of Mass states that in a chemical reaction, matter is neither created nor destroyed. This means that the total mass of reactants is equal to the total mass of products. Atoms are the building blocks of matter, so atoms cannot be destroyed (or created) during a chemical reaction. They are just rearranged to form new substances (products) from the reactants.
## Step2: Explain
During a chemical reaction, the atoms of the reactants are rearranged to form the products. The number of each type of atom remains the same before and after the reaction (this is why we balance chemical equations - to ensure the same number of each atom on both sides). So, according to the Law of Conservation of Mass, atoms cannot be destroyed during a reaction because the total mass of the system (reactants + products) must remain constant, and atoms are the particles that make up matter. If atoms were destroyed, mass would be lost, which violates the law.
# Answer: No, atoms cannot be destroyed during a reaction. According to the Law of Conservation of Mass, matter is neither created nor destroyed in a chemical reaction. Atoms are rearranged to form products from reactants, and the total number of each type of atom remains the same (mass is conserved), so atoms are not destroyed.

### Questions 31 - 38 (Identifying unbalanced equations)
#### Question 31: $ \ce{2H2 + O2 -> 2H2O} $
# Explanation:
## Step1: Count atoms
- Reactants: H: $ 2\times2 = 4 $, O: $ 2 $
- Products: H: $ 2\times2 = 4 $, O: $ 2\times1 = 2 $
- The number of H and O atoms is equal on both sides. So this equation is balanced and does not violate the Law of Conservation of Mass.
# Answer: No checkmark (equation is balanced)

#### Question 32: $ \ce{KCl + Br2 -> KBr + Cl2} $
# Explanation:
## Step1: Count atoms
- Reactants: K: 1, Cl: 1, Br: 2
- Products: K: 1, Br: 1, Cl: 2
- For K: 1 = 1 (good). For Br: 2 (reactants) vs 1 (products) - unbalanced. For Cl: 1 (reactants) vs 2 (products) - unbalanced. So this equation is unbalanced and violates the Law of Conservation of Mass.
# Answer: Checkmark (equation is unbalanced)

#### Question 33: $ \ce{Na2CO3 + 2HCl -> 2NaCl + H2O + CO2} $
# Explanation:
## Step1: Count atoms
- Reactants: Na: $ 2 $, C: 1, O: $ 3 + 2\times1 = 5 $ (wait, $ \ce{HCl} $ has O? No, $ \ce{HCl} $ is $ \ce{H+} $ and $ \ce{Cl-} $, so O is only in $ \ce{Na2CO3} $: 3. H: $ 2\times1 = 2 $, Cl: $ 2\times1 = 2 $, Na: 2, C: 1.
- Products: Na: $ 2\times1 = 2 $, Cl: $ 2\times1 = 2 $, H: $ 2\times1 = 2 $, O: $ 1 + 2 = 3 $ (in $ \ce{H2O} $: 1, in $ \ce{CO2} $: 2), C: 1.
- So Na: 2 = 2, C: 1 = 1, O: 3 = 3, H: 2 = 2, Cl: 2 = 2. The equation is balanced (the 2 in front of HCl and 2 in front of NaCl are correct). So no violation.
# Answer: No checkmark (equation is balanced)

#### Question 34: $ \ce{2Fe2O3 + 3C -> 4Fe + 3CO2} $
# Explanation:
## Step1: Count atoms
- Reactants: Fe: $ 2\times2 = 4 $, O: $ 2\times3 = 6 $, C: 3
- Products: Fe: 4, O: $ 3\times2 = 6 $, C: 3
- Fe: 4 = 4, O: 6 = 6, C: 3 = 3. The equation is balanced. So no violation.
# Answer: No checkmark (equation is balanced)

#### Question 35: $ \ce{Na + O2 -> Na2O} $
# Explanation:
## Step1: Count atoms
- Reactants: Na: 1, O: 2
- Products: Na: 2, O: 1
- Na: 1 vs 2 (unbalanced), O: 2 vs 1 (unbalanced). So the equation is unbalanced and violates the Law of Conservation of Mass.
# Answer: Checkmark (equation is unbalanced)

#### Question 36: $ \ce{2H2 + O2 -> 2H2O} $
# Explanation:
## Step1: Count atoms
- Reactants: H: $ 2\times2 = 4 $, O: 2
- Products: H: $ 2\times2 = 4 $, O: $ 2\times1 = 2 $
- Atoms are balanced. So no violation.
# Answer: No checkmark (equation is balanced)

#### Question 37: $ \ce{4H2 + 2O2 -> 4H2O} $
# Explanation:
## Step1: Count atoms
- Reactants: H: $ 4\times2 = 8 $, O: $ 2\times2 = 4 $
- Products: H: $ 4\times2 = 8 $, O: $ 4\times1 = 4 $
- Atoms are balanced (this is just a multiple of the balanced equation $ \ce{2H2 + O2 -> 2H2O} $, multiplied by 2). So no violation.
# Answer: No checkmark (equation is balanced)

#### Question 38: $ \ce{2H2 + O2 -> H2O} $
# Explanation:
## Step1: Count atoms
- Reactants: H: $ 2\times2 = 4 $, O: 2
- Products: H: $ 2\times1 = 2 $, O: 1
- H: 4 vs 2 (unbalanced), O: 2 vs 1 (unbalanced). So the equation is unbalanced and violates the Law of Conservation of Mass.
# Answer: Checkmark (equation is unbalanced)

### Question 39
# Explanation:
## Step1: Recall state symbols
In chemical equations, the state symbols are used to indicate the physical state of the substance. The symbol $ (l) $ stands for liquid. So in $ \ce{H2O(l)} $, it means water is in the liquid state.
## Step2: Confirm
Common state symbols: $ (s) $ for solid, $ (l) $ for liquid, $ (g) $ for gas, $ (aq) $ for aqueous (dissolved in water). So $ (l) $ is liquid.
# Answer: Liquid (the substance $ \ce{H2O} $ is in the liquid state)

### Question 40
# Explanation:
## Step1: Recall state symbols
The symbol $ (g) $ in a chemical equation stands for gas. So in $ \ce{O2(g)} $, it means oxygen is in the gaseous state.
## Step2: Confirm
State symbols: $ (s) $ - solid, $ (l) $ - liquid, $ (g) $ - gas, $ (aq) $ - aqueous. So $ (g) $ represents gas.
# Answer: Gas (the substance $ \ce{O2} $ is in the gaseous state)

### Question 41
# Explanation:
## Step1: Recall state symbols
The symbol $ (aq) $ in a chemical equation stands for aqueous, which means the substance is dissolved in water (in an aqueous solution). So in $ \ce{H2O2(aq)} $, it means hydrogen peroxide is dissolved in water (in an aqueous solution).
## Step2: Confirm
$ (aq) $ is the standard state symbol for aqueous solutions, indicating that the solute is dissolved in water.
# Answer: Aqueous (the substance $ \ce{H2O2} $ is dissolved in water, in an aqueous solution)

### Question 42
# Explanation:
## Step1: Recall state symbols
The state symbol $ (s) $ in a chemical equation stands for solid. So if a substance has the symbol $ (s) $ next to it, it means the substance is in the solid state.
## Step2: Confirm
Common state symbols: $ (s) $ - solid, $ (l) $ - liquid, $ (g) $ - gas, $ (aq) $ - aqueous. So $ (s) $ represents solid.
# Answer: Solid (the substance is in the solid state)

### Question 43
# Explanation:
## Step1: Recall reactants and products
In a chemical equation, the reactants are the substances on the left - hand side of the arrow (→), and the products are on the right - hand side. In the reaction $ \ce{H2O2(aq) -> H2O(l) + O2(g)} $, the reactant is the substance before the arrow, which is $ \ce{H2O2(aq)} $ (hydrogen peroxide in aqueous solution).
## Step2: Confirm
Reactants are the starting materials that undergo the reaction to form products. In the given equation, $ \ce{H2O2(aq)} $ is the reactant as it is on the left of the arrow.
# Answer: $ \ce{H2O2(aq)} $ (Hydrogen Peroxide in aqueous solution)

### Question 44
# Explanation:
## Step1: Recall reactants and products
In a chemical equation, the products are the substances on the right - hand side of the arrow (→). In the reaction $ \ce{H2O2(aq) -> H2O(l) + O2(g)} $, the products are the substances after the arrow, which are $ \ce{H2O(l)} $ (liquid water) and $ \ce{O2(g)} $ (gaseous oxygen).
## Step2:

Sovi.AI - AI Math Tutor

QUESTION IMAGE

Question

Explanation:

Question 26

Step1: Recall reaction types

Step2: Confirm

Step1: Recall combustion reaction

Step2: Confirm

Step1: Recall balancing chemical equations

Step2: Confirm

Answer:

Question 27