Question

25g of ice in a glass is placed outside in the morning. it is retrieved in the afternoon and is now water, but the temperature remained constant at 0°c. what is the total energy gained as the water melted?
a -8350 j
b 56500 j
c -56500 j
d 8350 j

Explanation:

Step1: Recall the formula for heat of fusion

The formula for the heat \(Q\) required for a phase change (melting in this case) is \(Q = mL_f\), where \(m\) is the mass and \(L_f\) is the latent heat of fusion. For water, \(L_f=334\space J/g\).

Step2: Substitute the values into the formula

Given \(m = 25\space g\) and \(L_f = 334\space J/g\). Then \(Q=(25\space g)\times(334\space J/g)\).

$$
LATEXBLOCK0
$$

Since heat is gained, the value is positive.

Answer:

D. \(8350\space J\)