Question

1. if 0.250 g of fuel increases the temperature of a calorimeter by 20 °c, and the calorimeter is calibrated at 7.28 kj/°c, calculate the heat of combustion of fuel per gram. show all your work.

Explanation:

Step1: Calculate the total heat released

The heat absorbed by the calorimeter \(q = C\times\Delta T\), where \(C = 7.28\space kJ/^{\circ}C\) (calorimeter constant) and \(\Delta T=20^{\circ}C\).

$$q = 7.28\times20=145.6\space kJ$$

Step2: Calculate the heat of combustion per gram

We know that \(m = 0.250\space g\) of fuel releases \(q = 145.6\space kJ\) of heat. The heat of combustion per gram \(H\) is given by \(H=\frac{q}{m}\)

$$H=\frac{145.6}{0.250}=582.4\space kJ/g$$

Answer:

\(582.4\space kJ/g\)