Question

1. determine the distance that a rock will travel in the y - direction if it has an initial velocity of 25 m/s and flies for 3.5 seconds.

50 meters
151 meters
31 meters

• 29.05 meters

Explanation:

Step1: Identify the formula

The formula for vertical displacement \(y = v_{0y}t-\frac{1}{2}gt^{2}\). Here, \(v_{0y}\) is the initial vertical velocity, \(t\) is the time, and \(g = 9.8\ m/s^{2}\) (acceleration due to gravity).

Step2: Substitute the values

Given \(v_{0y}=25\ m/s\), \(t = 3.5\ s\), and \(g=9.8\ m/s^{2}\).

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If we assume the upward - direction as positive, the rock first goes up and then comes down. The net displacement is calculated using the kinematic equation for vertical motion under gravity.

Answer:

• 29.05 meters