Question

1. if 60 liters of hydrogen gas at 546 k is cooled to 273 k at constant pressure, the new volume of the gas will be a) 120 l b) 20 l c) 30 l d) 40 l

Explanation:

Step1: Identify the gas - law formula

At constant pressure, we use Charles's law $\frac{V_1}{T_1}=\frac{V_2}{T_2}$.

Step2: Assign values

$V_1 = 60\ L$, $T_1=546\ K$, $T_2 = 273\ K$.

Step3: Solve for $V_2$

$V_2=\frac{V_1\times T_2}{T_1}=\frac{60\times273}{546}$.
$V_2 = 30\ L$.

Answer:

C. 30 L