QUESTION IMAGE
Question
- (1.06) if a quadrilateral does not have four right angles, then it is not a rectangle.
a. inverse
b. contrapositive
c. converse
d. either a or c
e. none of the above
- select the correct proof from the options listed.
given: rectangle (abcd); (m) is the midpoint of (overline{ad})
prove: (\triangle bmc) is isosceles
image of rectangle (abcd) with (m) as midpoint of (ad), and diagonals (bm) and (cm) drawn
a.
| statements | reasons |
|---|---|
| 2. (angle a) and (angle d) are right angles. | 2. definition of a right triangle |
| 3. (angle a cong angle d) | 3. all right angles are congruent. |
| 4. (m) is the midpoint of (overline{ad}). | 4. given |
| 5. (overline{am} cong overline{dm}) | 5. definition of a midpoint |
| 6. (overline{ab} cong overline{dc}) | 6. if a quadrilateral is a rectangle/parallelogram, then both pairs of opposite sides are congruent. |
| 7. (\triangle bam cong \triangle cdm) | 7. side - angle - side |
| 8. (overline{bm} cong overline{cm}) | 8. c.p.c.t.c. |
| 9. (\triangle bcm) is isosceles. | 9. definition of an isosceles triangle |
b.
| statements | reasons |
|---|---|
| 2. (angle a) and (angle d) are right angles. | 2. definition of a right triangle |
| 3. (angle a cong angle d) | 3. all right angles are congruent. |
| 4. (m) is the midpoint of (overline{ad}). | 4. given |
| 5. (overline{am} cong overline{dm}) | 5. definition of a right point |
| 6. (overline{ab} cong overline{dc}) | 6. if a quadrilateral is a rectangle/parallelogram, then both pairs of opposite sides are congruent. |
| 7. (\triangle bam cong \triangle cdm) | 7. side - angle - side |
| 8. (overline{bm} cong overline{cm}) | 8. c.p.c.t.c. |
| 9. (\triangle bcm) is isosceles. | 9. definition of an equilateral triangle |
c.
| statements | reasons |
|---|---|
| 2. (overline{ab} cong overline{dc}) | 2. diagonals of a rectangle are congruent. |
| 3. (\triangle bcm) is isosceles. | 3. definition of an isosceles triangle |
Step1: Analyze Option B
- In step 5 of Option B, the reason is "Definition of a right point", which is incorrect (should be "Definition of a midpoint").
- In step 9, the reason is "Definition of an equilateral triangle", but we need to prove it's isosceles, so this is wrong.
Step2: Analyze Option C
- Option C has only 3 statements. The reasoning is incomplete (it skips proving \( \overline{BM} \cong \overline{CM} \) properly) and the second reason ("Diagonals of a rectangle are congruent") is not relevant to showing \( \overline{AB} \cong \overline{DC} \) directly for this proof structure.
Step3: Analyze Option A
- Step 2: "∠A and ∠D are right angles" follows from the definition of a rectangle (not right triangle, but this is a minor wording issue, and the concept is correct as rectangles have right angles).
- Step 5: "Definition of a midpoint" correctly justifies \( \overline{AM} \cong \overline{DM} \).
- Step 7: Uses SAS ( \( \overline{AB} \cong \overline{DC} \), \( \angle A \cong \angle D \), \( \overline{AM} \cong \overline{DM} \)) to prove \( \triangle BAM \cong \triangle CDM \).
- Step 8: CPCTC (Corresponding Parts of Congruent Triangles are Congruent) gives \( \overline{BM} \cong \overline{CM} \).
- Step 9: Definition of isosceles triangle (a triangle with two congruent sides) correctly concludes \( \triangle BMC \) is isosceles.
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A.
- Rectangle \( ABCD \) - Given
- \( \angle A \) and \( \angle D \) are right angles. - Definition of a rectangle (note: wording "right triangle" is a typo, but concept holds)
- \( \angle A \cong \angle D \) - All right angles are congruent.
- \( M \) is the midpoint of \( \overline{AD} \). - Given
- \( \overline{AM} \cong \overline{DM} \) - Definition of a midpoint
- \( \overline{AB} \cong \overline{DC} \) - If a quadrilateral is a rectangle/parallelogram, then both pairs of opposite sides are congruent.
- \( \triangle BAM \cong \triangle CDM \) - Side - Angle - Side
- \( \overline{BM} \cong \overline{CM} \) - C.P.C.T.C.
- \( \triangle BCM \) is isosceles. - Definition of an isosceles triangle