Question

1. 21 ÷ 3 + 9x

Explanation:

Step1: Simplify the division

First, calculate \(21\div3\). \(21\div3 = 7\), so the expression becomes \(7 + 9x\).
(Assuming we want to solve for \(x\) when \(7 + 9x=\) some value, but since the problem's full context for solving isn't clear, if we assume it's an equation like \(21\div3 + 9x=\) a number, maybe from the crossed - out part, but if we assume we are simplifying the expression, the simplified form is \(7 + 9x\). If we assume it's an equation, say if we had \(21\div3+9x = 34\) (just an example to show solving), but from the given, maybe the original problem was to solve \(21\div3 + 9x=\) a value. Wait, maybe the user made a typo, but if we proceed with simplifying the given expression \(21\div3+9x\))

Step2: Final simplification

After calculating \(21\div3 = 7\), the expression \(21\div3 + 9x\) simplifies to \(7+9x\).

If we assume the equation was \(21\div3 + 9x=34\) (to solve for \(x\)):

Step1: Simplify the left - hand side

\(21\div3+9x=7 + 9x\)

Step2: Subtract 7 from both sides

\(7+9x - 7=34 - 7\)
\(9x=27\)

Step3: Divide both sides by 9

\(x = \frac{27}{9}=3\)

Since the original problem's full context is a bit unclear, but if we go with solving for \(x\) (assuming the equation was \(21\div3 + 9x = 34\) or similar to get \(x = 3\) as a possible solution):

Answer:

If simplifying the expression: \(7 + 9x\); If solving for \(x\) (assuming a typical equation context) \(x = 3\)