Question

1. a 2000 - lb wheel load is to be supported by aggregate over soil that can withstand a pressure of 1000 lb/sq. ft. what depth of aggregate is needed if \\( \theta = 40 ^ { \circ } \\)?

Explanation:

Step1: Convert wheel load to force

The wheel load is \(F = 2000\space lb\).

Step2: Use the formula for pressure \(p=\frac{F}{A}\)

We know \(p = 1000\space lb/sq.ft\) and \(F=2000\space lb\). Rearranging the formula for \(A\) (area), we get \(A=\frac{F}{p}\).
Substitute \(F = 2000\) and \(p = 1000\) into the formula: \(A=\frac{2000}{1000}\)

Step3: Calculate the area

\(A = 2\space sq.ft\)

Answer:

The required area \(A\) is \(2\space sq.ft\)