Question

1. janice plans to roll all the quarters in her desk drawer. it takes $10 in quarters to fill one quarter roll. she has already placed at least 7 quarters in a paper roll. the inequality shown below can be used to calculate n, the number of quarters that can fit into one roll.

n + 7 ≤ 40

which inequality represents the solution set for the remaining number of quarters janice can fit into the roll she has started to fill?
a. n ≤ 33
b. n ≥ 33
c. n ≤ 47
d. n ≥ 47

1. hector brought a 16 pound bag of dog food for $18. the bag will feed his dog for a month. hector wanted to know how much he was spending per pound to feed his dog. he created the model shown to help determine the cost (c).

chart: a bar divided into 16 parts labeled c
what was the cost of the dog food per pound?
f. $1.13
g. $9.00
h. $18.00
j. $113.00

1. which algebraic equation is represented by the model below?

image: 8 black rectangles labeled x, 1 white square labeled 1 on left; 9 squares on right with some shaded
a. 8x + 1 = 9
b. 8x - 1 = -9
c. -8x - 1 = -9
d. -8x + 1 = 9

Explanation:

Question 20

Step1: Resolver la desigualdad

Para resolver \( n + 7 \leq 40 \), restamos 7 de ambos lados: \( n + 7 - 7 \leq 40 - 7 \)

Step2: Simplificar

Simplificando, obtenemos \( n \leq 33 \)

Step1: Definir la fórmula

El costo por libra \( c \) se calcula como \( c=\frac{\text{precio total}}{\text{peso total}} \)

Step2: Sustituir valores

Sustituimos precio total = \$18 y peso total = 16 libras: \( c = \frac{18}{16} \)

Step3: Calcular

\( \frac{18}{16}=1.125\approx1.13 \)

Step1: Analizar el modelo

Del lado izquierdo, hay 8 rectángulos de \( x \) y 1 unidad positiva. Del lado derecho, hay 9 unidades positivas (ya que la cuadrícula tiene 9 casillas positivas, suponiendo que cada casilla es 1).

Step2: Escribir la ecuación

Así, la ecuación es \( 8x + 1 = 9 \)

Answer:

A. \( n \leq 33 \)

Question 21