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f(-2) = \\frac{(-2)^2 + 2(-2)}{-2 - 5} f(-2) = \\underline{\\quad\\quad}

Question

f(-2) = \frac{(-2)^2 + 2(-2)}{-2 - 5} f(-2) = \underline{\quad\quad}

Explanation:

Step1: Calculate numerator

First, calculate the numerator \((-2)^2 + 2(-2)\). We know that \((-2)^2 = 4\) and \(2(-2)= -4\). So, \(4 + (-4)=0\).

Step2: Calculate denominator

Next, calculate the denominator \(-2 - 5=-7\).

Step3: Divide numerator by denominator

Now, divide the numerator (which is 0) by the denominator (which is -7). So, \(\frac{0}{-7} = 0\).

Answer:

\(0\)