Question

1. given $sin\theta$, write $sin(-\theta)$. $sin60{}^{\circ }=\frac{\sqrt{3}}{2}$

Explanation:

Step1: Use the trigonometric identity for sine of negative angle

The identity is $\sin(-\theta)=-\sin\theta$.

Step2: Substitute $\theta = 60^{\circ}$

Since $\sin60^{\circ}=\frac{\sqrt{3}}{2}$, then $\sin(-60^{\circ})=-\sin60^{\circ}$.

Answer:

$\sin(-60^{\circ})=-\frac{\sqrt{3}}{2}$