Question

1. ethylene glycol, the main component of automotive engine coolant, has a specific heat of 2.35 j/g°c. calculate the amount of heat required to raise the temperature of 1.00 kg of ethylene glycol from 20.0°c to 80.0°c.

a. 1.71×10⁴ j
b. 1.00×10³ j
c. 1.41×10² j
d. 2.35×10³ j
e. 1.41×10⁵ j

Explanation:

Step1: Convert mass to grams

Since \(1\ kg = 1000\ g\), so \(m = 1.00\ kg=1000\ g\)

Step2: Calculate the temperature change

\(\Delta T=T_{final}-T_{initial}\)
\(\Delta T = 80.0^{\circ}C - 20.0^{\circ}C=60.0^{\circ}C\)

Step3: Use the heat formula \(Q = mc\Delta T\)

Given \(c = 2.35\ J/g^{\circ}C\), \(m = 1000\ g\), \(\Delta T=60.0^{\circ}C\)
\(Q=(1000\ g)\times(2.35\ J/g^{\circ}C)\times(60.0^{\circ}C)\)
\(Q = 2.35\times60\times1000\ J\)
\(Q=141000\ J = 1.41\times 10^{5}\ J\)

Answer:

E. \(1.41\times 10^{5}\ J\)