Question

1. what are the values of x for which the denominator is equal to zero for $y = \frac{-x + 4}{x^2 + 6x + 8}$?

$x = 2, x = 4$
$x = -2, x = -4$
$x = 2, x = -4$
no points of discontinuity

Explanation:

Step1: Set denominator to zero

$x^2 + 6x + 8 = 0$

Step2: Factor quadratic equation

$(x + 2)(x + 4) = 0$

Step3: Solve for x

$x + 2 = 0 \Rightarrow x=-2$; $x + 4 = 0 \Rightarrow x=-4$

Answer:

x=-2, x=-4