Question

1. if 16,700 j of work is done to shoot the human cannonball down a 3.05 m barrel, then how much force is applied to the person to fire them out the cannon?
2. an elephant pushes with 2000 n on a load of trees. it then pushes these trees for 150 m. how much work did the elephant do?
3. an 190,000 w engine can accelerate from rest to a top speed in 9 s. how much work did the engine do?
4. another engine reaches its top speed from rest in 7.5 s. it is able to perform 250,000 j of work in that time. how much power does this engine have in that time?
5. if a runner exerts 350 j of work to make 125 w of power, then how long did it take the runner to do the work?

Explanation:

Question 6

Step1: Recall the work formula

Work \(W = F\times d\), where \(W\) is work, \(F\) is force, and \(d\) is distance. We need to solve for \(F\), so \(F=\frac{W}{d}\).

Step2: Substitute the values

Given \(W = 16700\space J\) and \(d=3.05\space m\). Then \(F=\frac{16700}{3.05}\).

Step3: Calculate the value

\(F=\frac{16700}{3.05}\approx5475.41\space N\)

Step1: Use the work formula

Work \(W = F\times d\). Here \(F = 2000\space N\) and \(d = 150\space m\)

Step2: Calculate the work

\(W=2000\times150\)
\(W = 300000\space J\)

Step1: Recall the power formula

Power \(P=\frac{W}{t}\), so \(W = P\times t\)

Step2: Substitute the values

Given \(P = 190000\space W\) and \(t = 9\space s\)
\(W=190000\times9\)
\(W = 1710000\space J\)

Answer:

The force applied is approximately \(5475.41\space N\)

Question 7