a 1520 kg car in motion rolls down a frictionless hill that is inclined at (14.4^{circ}).

if the hill is 28.5 m long, what is the velocity of the car as it reaches the base of the hill?

(a = 2.44\text{ m/s}^2)

(v_f = ?\text{ m/s})

Question

a 1520 kg car in motion rolls down a frictionless hill that is inclined at (14.4^{circ}).

if the hill is 28.5 m long, what is the velocity of the car as it reaches the base of the hill?

(a = 2.44\text{ m/s}^2)

(v_f = ?\text{ m/s})

Accepted Answer

# Explanation:

⚡ Using what you learned: conservation of mechanical energy

## Step 1: Identify given values

$$
\begin{aligned}
m &= 1520\text{ kg} \
\theta &= 14.4^\circ \
d &= 28.5\text{ m} \
a &= 2.44\text{ m/s}^2 \
v_i &= 0\text{ m/s}
\end{aligned}
$$

## Step 2: Calculate final velocity using kinematic equations

$$
\begin{aligned}
v_f^2 &= v_i^2 + 2ad \
v_f^2 &= 0^2 + 2(2.44)(28.5) \
v_f^2 &= 139.08 \
v_f &= \sqrt{139.08} \
v_f &\approx 11.8\text{ m/s}
\end{aligned}
$$

# Answer:

11.8

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QUESTION IMAGE

Question

Explanation:

Step 1: Identify given values

Step 2: Calculate final velocity using kinematic equations

Answer: