Question

15 starting from rest, a car undergoes a constant acceleration of ( 5 mathrm{~m} / mathrm{s}^{2} ). how far will the car travel in 1.5 seconds? (write your answer in 2 significant figures)

Explanation:

Step1: Identify the kinematic equation

Since the car starts from rest ($v_0 = 0$), we use the equation $s=v_0t+\frac{1}{2}at^{2}$.

Step2: Substitute the values

Substitute $v_0 = 0$, $a = 5\ m/s^{2}$, and $t = 1.5\ s$ into the formula. So $s=0\times1.5+\frac{1}{2}\times5\times(1.5)^{2}$.

Step3: Calculate the distance

First, $(1.5)^{2}=2.25$. Then $\frac{1}{2}\times5\times2.25=\frac{11.25}{2}=5.625$. Rounding to 2 significant figures.

Answer:

$5.6\ m$