Question

15 multiple choice 1 point iron (iii) selenide fe₂se₃ fe₃se fese fe₃se₂

Explanation:

Step1: Determine the charges

Iron (III) has a charge of \(Fe^{3+}\). Selenide (\(Se\)) has a charge of \(Se^{2 -}\) (since it is in group 16 of the periodic table and gains 2 electrons to achieve a stable octet).

Step2: Use the criss - cross method

To form a neutral compound, we use the criss - cross method. The magnitude of the charge of \(Fe^{3+}\) (which is 3) becomes the subscript of \(Se\), and the magnitude of the charge of \(Se^{2-}\) (which is 2) becomes the subscript of \(Fe\). So the formula is \(Fe_{2}Se_{3}\)

Answer:

\(Fe_{2}Se_{3}\) (the first option)