Question

1 a 15 - foot tall tree is next to a slide. the tree is casting a shadow of 22.5 feet and the slide is casting a shadow that is 10.5 feet. how tall is the slide? f 7 ft g 15 ft h 25 ft j 33 ft 3 in the figures below, \\( \triangle qsr\sim\triangle xyz \\). what is the length of \\( \overline{qr} \\)? f 33 g 25 h 13 j 11 the 2008 yearbook at middleton middle school had 236 candid pictures of students. the 2007 yearbook had 214 candid pictures of students. what was the percent of change in the number of candid

Explanation:

Step1: Use the property of similar triangles

Since \(\triangle QSR\sim\triangle XYZ\), the ratios of corresponding sides are equal. That is \(\frac{QR}{XZ}=\frac{SR}{YZ}\)

Step2: Substitute the known values

We know \(SR = 20\), \(YZ=8\), and \(XZ = 10\). Let \(QR=x\). Then \(\frac{x}{10}=\frac{20}{8}\)

Step3: Solve for \(x\)

Cross - multiply: \(8x=20\times10\), so \(8x = 200\). Then \(x=\frac{200}{8}=25\)

Answer:

G. 25