Question

1. \\( \frac{8}{4} \cdot 6 \cdot 2 + 5 - 1 \\)\
2. \\( 5 \cdot 3 - 2 + (6 - 3)^2 \\)\

\\( 15 - 2 + (3)^2 \\)\
\\( 13 + 9 = 22 \\)\
evaluate each using the values given. (4pts each)\

1. \\( y - x^2 + 4 \\); use \\( x = 2 \\), and \\( y = 6 \\)\
2. \\( rq - q + 2 \\); use \\( q = 3 \\), and \\( r = 2 \\)

Explanation:

Step1: Simplify fraction

Simplify \(\frac{8}{4}\) to get \(2\).
\(\frac{8}{4} = 2\)

Step2: Multiply and add/subtract

Now calculate \(2 \cdot 6 \cdot 2 + 5 - 1\). First, multiply \(2 \cdot 6 = 12\), then \(12 \cdot 2 = 24\). Then add \(5\) to get \(24 + 5 = 29\), and subtract \(1\): \(29 - 1 = 28\).
\(2 \cdot 6 \cdot 2 + 5 - 1 = 24 + 5 - 1 = 28\)

Step3: Evaluate expression 9

For \(y - x^{2}+4\) with \(x = 2\) and \(y = 6\), first calculate \(x^{2}=2^{2}=4\). Then substitute: \(6 - 4 + 4\). Subtract \(4\) from \(6\) to get \(2\), then add \(4\): \(2 + 4 = 6\).
\(y - x^{2}+4 = 6 - 2^{2}+4 = 6 - 4 + 4 = 6\)

Step4: Evaluate expression 10

For \(rq - q + 2\) with \(q = 3\) and \(r = 2\), substitute values: \(2\cdot3 - 3 + 2\). Multiply \(2\cdot3 = 6\), then subtract \(3\): \(6 - 3 = 3\), then add \(2\): \(3 + 2 = 5\).
\(rq - q + 2 = 2\cdot3 - 3 + 2 = 6 - 3 + 2 = 5\)

Answer:

s:

• Problem 7 (assuming the first problem is \(\frac{8}{4}\cdot6\cdot2 + 5 - 1\)): \(28\)
• Problem 9: \(6\)
• Problem 10: \(5\)